I am not an expert in mixed effect modelling, but the question is much easier to answer if it is rephrased in hierarchical regression modelling context. So our observations have two indexes $P_{ij}$ and $F_{ij}$ with index $i$ representing class and $j$ members of the class. The hierarchical models let us fit linear regression, where coefficients vary across classes:
$$Y_{ij}=\beta_{0i}+\beta_{1i}F_{ij}$$
This is our first level regression. The second level regression is done on the first regression coefficients:
\begin{align*}
\beta_{0i}&=\gamma_{00}+u_{0i}\\
\beta_{1i}&=\gamma_{01}+u_{1i}
\end{align*}
when we substitute this in first level regression we get
\begin{align*}
Y_{ij}&=(\gamma_0+u_{0i})+(\gamma_{01}+u_{1i})F_{ij}\\
&=\gamma_0+u_{0i}+u_{1i}F_{ij}+\gamma_{01}F_{ij}
\end{align*}
Here $\gamma$ are fixed effects and $u$ are random effects. Mixed model estimates $\gamma$ and variances of $u$.
The model I've written down corresponds to lmer syntax
P ~ (1+F|R) + F
Now if we put $\beta_{1i}=\gamma_{01}$ without the random term we get
\begin{align*}
Y_{ij}=\gamma_0+u_{0i}+\gamma_{01}F_{ij}
\end{align*}
which corresponds to lmer syntax
P ~ (1|R) + F
So the question now becomes when can we exclude error term from the second level regression? The canonical answer is that when we are sure that the regressors (here we do not have any, but we can include them, they naturally are constant within classes) in the second level regression fully explain the variance of coefficients across classes.
So in this particular case if coefficient of $F_{ij}$ does not vary, or alternatively the variance of $u_{1i}$ is very small we should entertain idea that we are probably better of with the first model.
Note. I've only gave algebraic explanation, but I think having it in mind it is much easier to think of particular applied example.