Tell me more ×
Cross Validated is a question and answer site for statisticians, data analysts, data miners and data visualization experts. It's 100% free, no registration required.

Given a Gaussian distribution $N(\mu_1,\sigma_1^2)$, i would like to choose another mean $\mu_2$ which is $2\sigma_1$ away from $\mu_1$. In this case our new mean $\mu_2=\mu_1\pm 2\sigma_1$.

How do we calculate the new mean($\mu_2$) in multivariate case?

I mean to say, when your multivariate Gaussian distribution is $N(\mu_1,\Sigma_1)$ and my $\Sigma_1$ is symmetric positive definite matrix. i.e $\left[ \begin{array}{cc} \sigma_x^2 & \sigma_{xy} \\ \sigma_{yx} & \sigma_y^2 \end{array} \right]$.

share|improve this question
I am not sure that I understand even the univariate case. By $\mu_2=\mu_1\pm 2\sigma_1$ you mean that both answers are ok? – mpiktas Apr 27 '11 at 10:24
1  
what is the context of this problem? As it stands now, it is impossible to answer, since in multivariate case the means are vectors and the distance between them is a number, but the covariance matrix is not. – mpiktas Apr 27 '11 at 10:26

1 Answer

up vote 1 down vote accepted

In the bivariate case you can substitute the two points ($\mu_2=\mu_1\pm 2\sigma_1$) with an isodensity ellipse: http://www.stat.psu.edu/online/courses/stat505/05_multnorm/06_multnorm_revist.html .

Your $2\sigma_1$ criterion seems a bit arbitrary, but it includes 95.44997% of the random variable. So you may want to use the 95.44997% isodensity ellipse in the bivariate case, too. The principle axes of this rotated ellipse are the eigenvectors of the covariance matrix, see http://web.as.uky.edu/statistics/users/viele/sta601s08/multinorm.pdf . You can generalise this to more than 2 dimensions.

share|improve this answer

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.