# Always get confused by “probabilities and weighted probabilities” type of questions as cant differentiate between two

Urn 1 contains 5 white balls and 7 black balls. Urn 2 contains 3 whites and 12 black. A fair coin is flipped; if it is Heads, a ball is drawn from Urn 1, and if it is Tails, a ball is drawn from Urn 2. Suppose that this experiment is done and you learn that a white ball was selected. What is the probability of choosing a white ball?

I thought P(W) = 8/27 or 0.29 since P(H or T) = 0.5

BUT P(W) = P(W|T) P(T) + P(W|T') P(T') = 3/15 x 1/2 + 5/12 x 1/2 = 1/10 + 5/24 = 37/120 (= 0.302)

I understand the even though getting H or T is same, the frequency of white balls in each urn is different. But I still think probability is 8/27 (of course I am wrong but dont know how to change my opinion). Could someone better explain whats happening and/or point me to other examples? I always get such questions wrong and want to train myself instinctively for such weighted probabilities. Need to train myself to spot them.

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 But wouldnt P(W) still be 1001/2001 OR 1/2000? – user18601 Jan 12 at 14:12 Of course not, if you have 1000 black balls in the first urn and only one white ball in the second urn, you see that the probability of picking a white ball is equivalent to the probability of picking the second urn ($=\frac{1}{2}$), that is having Tail when the coin is flipped. Try to picture the experiment in your head and count the number of times you pick a white ball as opposed to a black ball. – ThePawn Jan 12 at 14:19 this clarified everything. thanks a lot!!! – user18601 Jan 12 at 23:09 Looking at extremes is indeed useful general advice for checking one's thinking--as well as one's calculations. (+1) – whuber♦ Mar 13 at 20:43