Since standardized betas are correlation coefficients in bivariate regression, is it the case that standardized betas in multiple regression are partial correlations?
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Longer answer. If I have this right -- Partial correlation: $$ r_{y1.2} = \frac{r_{y1}-r_{y2}r_{12}}{\sqrt{(1-r^2_{y2})(1-r^2_{12})}} $$ equivalent standardized beta: $$ \beta_1 = \frac{r_{y1}-r_{y2}r_{12}}{\sqrt{(1-r^2_{12})}} $$ As you see, the denominator is different. Indeed, since the additional term in the denominator of the first thing is between 0 and 1 (inclusive), it looks like $\beta_1$ will almost always be smaller than $r_{y1.2}$ though they could be equal if the two "independent variables" (and here's why I dislike that term) are ... well, independent - or at least uncorrelated. |
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I've in another question the following covariance matrix C for the three variables X,Y,Z given: $$ \beta =\small \left[ \begin{array} {rrr} X\\Y\\Z \end{array} \right] = \small \left[ \begin{array} {rrr} 1&.&.\\ .&1&.\\ -0.199254&0.871240&0.319215 \end{array} \right] $$ which indicates, that the $\beta_X$ contribution for $Z$ is $\small \beta_X=-0.199254$ and the $\beta_Y$ contribution for $Z$ is $\small \beta_Y=0.871240$ . The unexplained variance in Z is the bottom-right entry squared: $\small resid^2= (0.319215)^2$ So - to come back to your question- the partial correlation between $Y$ and $Z$ were the product of the entries in the second column of the L-matrix. The $ \small \beta_Y$ however is the product of the entry in the second column of the Z-row with the inverse of that in the Y-row and the relation between the concepts of partial correlation and $\small \beta$ can be described by this observation. Additional comment: I find it a nice feature, that we get by this also the compositions of $X$ and $Y$ in terms of $X$ and $Y$ - which of course are trivially 1. It is also obvious, how we would proceed, if we had a second dependent variable, say $W$, and even that scheme can smoothly be extended to compute/show the coefficients of the generalization to the canonical correlation - but that's another story.... |
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