# How do I “vectorize” calls to dpois?

I am not sure if this is an instance of vectorizing the operations in R, but this is where I am stuck:

I want to get:

dpois(1, 0.1)
dpois(2, 0.2)
dpois(3, 0.3)


and I tried:

dpois(1:3, 0.1:0.3)


and

do.call(dpois, list(x = 1:3, lambda = 0.1:0.3))


both do not work.

It there a R-ish way of doing this?

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This isn't really about vectorizing calls to dpois. It's more a question about creating vectors. –  ashaw Feb 28 '11 at 16:49
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## 1 Answer

From help(dpois) it looks like you need x and lambda to be vectors (read more about object classes in the R Intro or any other R documentation to understand what this means).

The following works:

dpois(1:3, c(seq(0.1, 0.3, .1)))

Your first attempt fails because you are not concatenating (see: help(c)) the values for 0.1:0.3 into a vector and you are not providing any way for R to know what you want it to do with 0.1:0.3. Calling seq() in the manner above tells it to get a sequence from 0.1 to 0.3 by 0.1.

Your second attempt is pretty far into the weeds. There's no way you need a power-tool like do.call for this kind of thing.

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I should have looked at this carefully. –  suncoolsu Feb 28 '11 at 16:59
no worries, glad I could answer the question. –  ashaw Feb 28 '11 at 17:03
The only problem is with the 0.1:0.3 part. 1:3 is already a vector and doesn't require concatenation. –  Fojtasek Feb 28 '11 at 17:08
indeed. edited accordingly. –  ashaw Feb 28 '11 at 17:15
A more compact version of the same answer: dpois(1:3, 1:3/10). –  Joshua Ulrich Feb 28 '11 at 18:33
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