Tell me more ×
Cross Validated is a question and answer site for statisticians, data analysts, data miners and data visualization experts. It's 100% free, no registration required.

If I find that my covariate (reaction time) alters over the length of my experiment (e.g. due to fatigue), can I somehow build that into my model?
So what I am saying is that the effect of my covariate is not constant (between subjects and within subjects).

share|improve this question
Could you elaborate on your design a little more. How many times did you measure your covariate and dependent variable? Is covariate and dependent variable aligned in terms of time points? What experimental manipulation did you use? Is the experimental manipulation assumed to influence the covariate also? – Jeromy Anglim Aug 25 '11 at 5:52

2 Answers

Your covariate is not only different across subjects, but also gets different during the multiple measurements on the same subject. This has implications on the study design and the analysis method as well. (I'm not sure if you really meant the effect of the covariate in your second sentence.)

Study design: if your multiple measurements on the same subject are of various natures it's important that you run the measurements in various orders so as to be able to separate the effect of increasing fatigue from the effect of the natures of measurement.

Analysis: some statistical software require the dataset of repeated measure ANCOVA be formatted in the wide format, some other software require the long format (example for wide/long, permalink). Only in the long format will you be able to specify multiple RTs per subject. You will need a statistical software that supports the long format for repeated measures ANCOVA.

share|improve this answer

If you're interested in parsing a measure of fatigue from your RT data for use as a covariate, then I'd suggest computing the slope of RT as a function of time. An additional measure of "noisiness" might be the variance of RT once the effect of time has been removed.

share|improve this answer

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.