Cross Validated is a question and answer site for people interested in statistics, machine learning, data analysis, data mining, and data visualization. It's 100% free, no registration required.

Sign up
Here's how it works:
  1. Anybody can ask a question
  2. Anybody can answer
  3. The best answers are voted up and rise to the top

Can we change the acceptance rate in the random walk Metropolis algorithm by changing the parameter of the proposal distribution?

Let the target distribution be $\pi$. Let $p(x_2 | x_1)$ be the proposal density for a new state $x_2$ at current state $x_1$. The acceptance rate is $$ \alpha = \min(1, \frac{\pi(x_2) p(x_1|x_2)}{\pi(x_1) p(x_2|x_1)}) $$

If I am correct, in the random walk Metropolis algorithm, the proposal density is symmetric in the sense that $p(x_2 | x_1) = p(x_1 | x_2)$, so the acceptance rate doesn't depend on the proposal density, but only on the target distribution $\pi$ to be sampled. So changing the parameter of the proposal distribution will not change the acceptance rate $\alpha$.

For example, if the proposal distribution, at current state $x_1$, is a Gaussian distribution centered at the current state with a constant variance, i.e. $N(x_1, \sigma^2)$, which is by the way symmetric in the above sense, will changing the variance $\sigma^2$ of the Gaussian proposal distribution not change the acceptance rate $\alpha$?


share|improve this question

If your proposal has very a low variance, then your proposed new state will be very similar to the current state, so $\frac{\pi(x_2)}{\pi(x_1)}$ will be close to 1 (in the limit, with 0 variance, the proposal and current state will be same and you'll have it exactly equal to 1), so acceptance rate will be close to 100%.

If your proposal has high variance, however, $\frac{\pi(x_2)}{\pi(x_1)}$ will (at least sometimes) be way smaller than 1, so your acceptance rate will get closer and closer to 0%. So the acceptance rate decreases as the variance of the proposal increases.

The problem with very low variances (which will get you higher acceptance rate) is that they take longer to explore the posterior space by never moving far away from the current state. Adaptive MCMC methods like Haario et Al. try to handle such problem by changing the variance matrix of the proposal on the fly.

To tune your acceptance rate you could just try increase and decrease the variance, a somewhat trial and error approach. But depending on the geometry of the posterior, the acceptance rate might change drastically during the sampling process. Also, for multiparameter models the proposal covariance matrix has many variance and covariance terms and such method gets impractical.

There is more sofiscated methods to handle this like the adaptative metropolis method outlined in the link above, or you might want to take a look at other methods like those listed here. You may also try software like Jags and Stan if Metropolis doesn't work for your problem.

share|improve this answer
Thanks! can you see my updated post? by "Pr(proposal state)", do you mean "Pr(proposal state | current state)"? – Tim Feb 28 '14 at 18:45
Hi, in your new notation I meant $\pi(x_2)/\pi(x_1)$. I didn't bother with $p(x_1|x_2)/p(x_2|x_1)$ since you said you are working with a symmetric proposal, and therefore their relation is constant and equal to 1 for whichever variance you choose. – random_user Feb 28 '14 at 19:05
Thanks! How do you tune the variance of the proposal distribution, so that the acceptance rate fails between 0.2 and 0.5? – Tim Feb 28 '14 at 19:16
Expanded the answer a little to account for this. – random_user Feb 28 '14 at 19:34
It will depend on the geometry of posterior AFAIK. If your posterior is a normal distribution or something close to it and if you have a proposal distribution that is also a normal, I don't see why you couldn't "control" your acceptance rate doing trial and error in the variance of the proposal. Of course, real problems can be (and are) way more complex than this. – random_user Feb 28 '14 at 20:25

Your Answer


By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.