# Ronald

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# 7 Comments

 May14 comment How can adding a 2nd IV make the 1st IV significant? So, I understand that $X_1$ explains the variability that $X_2$ does not. Does this require that $X_2$ be (more) significant than $X_1$? Or can $X_1$ be made significant without significance of $X_2$? May14 comment DNA use in court cases I also calculate 1/80,000. May11 comment Confidence interval: “$v_2$ is at most $x$ larger than $v_1$, with a confidence of $95\%$” I tagged it because stats questions tend to get better and more thorough answers on stats.SE...! Apr15 comment Why does a 95% CI not imply a 95% chance of containing the mean? "Less than 94%" in a sample of 1000 CIs is surely not significant evidence against the idea that 95% of CIs contain the mean. In fact, I would expect 95% of CIs to indeed contain the mean, in this case. Apr15 comment Why does a 95% CI not imply a 95% chance of containing the mean? Link as requested. Ah yes. Within this example, it seems clear: if we do an experiment, there is a 75% chance that the resulting Confidence Interval will contain the mean. Once we've done the experiment and we know how it played out, that probability may be different, depending on the distribution of the resulting sample. Apr15 comment Why does a 95% CI not imply a 95% chance of containing the mean? strongly agree: "its probability is either 1 or 0" is not a natural way of looking at probability. Probability is otherwise measured given the best of your (subjective) knowledge; probability doesn't ever make sense as an objective, universal truth. The probability of the coin showing heads is different for you and for your friend who has had a peek! Apr15 comment Why does a 95% CI not imply a 95% chance of containing the mean? can you provide a direct link/page reference to that example? I searched the chapter but I could not identify the correct example.