network profile
| bio | website | |
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| visits | member for | 6 months |
| seen | Jan 18 at 1:22 | |
| stats | profile views | 13 |
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Jan 17 |
awarded | Editor |
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Nov 12 |
awarded | Commentator |
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Nov 11 |
comment |
Probability error - binary message Max, tks. Really is new for me. How i can edit equation? |
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Nov 11 |
comment |
Probability error - binary message Suppose ni is independent of any other component as well as the xi 's. Each component of y is decoded by the same rule used in part (a). The receiver uses majority rule to determine which symbol was transmitted. The decoding rules of the recipient are: o If two or more components of y are greater than zero, then one concludes that the token has been sent. o If two or more components of y are less than zero, then concludes that the token has been sent 0 Determine (find) the probability of error for this scheme modified encoding / decoding. |
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Nov 11 |
comment |
Probability error - binary message right i will work this information. The 2nd question from this problem is: (b) To reduce the probability of error, the following modifications are made. The transmitter encodes the symbols by using a repetition scheme. The symbol “0” is encoded by the vector x = [-2, -2, -2] T and symbol “1” is encoded by the vector x = [2, 2, 2] T. The vector y = [y1, y2, y3] T received at the destination is written as y = x + n. The vector n = [n1, n2, n3] is the noise vector where each “ni” is a Gaussian random variable with mean zero and variance σ2 = 4. |
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Nov 11 |
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Probability error - binary message Max, about n ~ N(0,4) is a normal distribuition, right? But sorry, after is not clear and about 68, 95 e 99.7 rules? tks |
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Nov 11 |
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Probability error - binary message Each symbol occurs with equal probability. The next question (2) for this original problema request is: "To reduce the probability of error, the following modifications are made...." I will edit the full question next time. Tks Dilip. |
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Nov 10 |
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Probability error - binary message Dear Max, tks for y help. I understand your information but I could not see how to rewrite the probability. |
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Nov 7 |
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Probability error - binary message Dear Gung, Tks for your note. Sorry, letter (b) is another question. (If "Y" .....) are information from the original question and not from de letter (b) that will be answer after (a). Bit error probability .... is the beginning of my reasoning "e" = "and" about tag that´s ok. tks |
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Nov 4 |
awarded | Student |
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Nov 4 |
asked | Probability error - binary message |
