| bio | website | biostat.mc.vanderbilt.edu/… |
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| seen | 8 hours ago | |
| stats | profile views | 2,384 |
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17h |
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Why do Friedman and Wilcoxon post-hoc contradict each other for my data? @xmjx be sure not to make the "absence of evidence is not evidence for absence" mistake. You would need to base you "if there is a difference" assessment on confidence intervals excluding meaningful differences, not on large P-values. |
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19h |
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Why do Friedman and Wilcoxon post-hoc contradict each other for my data? Note that the Friedman test in most situations has far less power than Wilcoxon-type tests. A generalization of the Wilcoxon test that is more suited to your situation is the mixed effects proportional odds model. But a quick and only slightly dirty approach is to use multiple Wilcoxon tests as you have done. On a more general note, even if the best available method resulted in a large P-value, the time was not wasted in the lab; it's just that many people are biased against "negative" studies. It is possible to learn a great deal from negative studies. |
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1d |
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Test accuracy higher than training. How to interpret? It is useful to know the accuracy on the training set in order to estimate the amount of overfitting your predictive algorithm has done (by computing the difference in accuracy between training & test sets). |
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2d |
answered | Test accuracy higher than training. How to interpret? |
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Jun 16 |
answered | Example of distribution where large sample size is necessary for central limit theorem |
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Jun 16 |
awarded | Nice Answer |
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Jun 15 |
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What are common statistical sins? In general it takes an enormous dataset for data splitting to be reliable. That's why stringent internal validation with the bootstrap is so attractive. |
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Jun 13 |
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Help me fit this non-linear multiple regression that has defied all previous efforts If you use linux I can give it to you now, otherwise expect 2 weeks. |
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Jun 12 |
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Help me fit this non-linear multiple regression that has defied all previous efforts Just do the binning temporarily unless we have the continuous solution. You can bin into 100 percentiles, e.g. require(Hmisc); cut2(y, g=100, levels.mean=TRUE) |
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Jun 12 |
answered | Help me fit this non-linear multiple regression that has defied all previous efforts |
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Jun 12 |
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Is it reasonable to compare a regression model with machine learing algorithms using RMSE? $R^2$ is another excellent measure, but if calculated the usual way allows for a linear recalibration of the predictions so does not penalize for predictions being off by a constant or a constant multiple. |
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Jun 12 |
answered | Is it reasonable to compare a regression model with machine learing algorithms using RMSE? |
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Jun 11 |
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Binary choice model and classification I would say that a probability model provides an estimate of Prob[Y=j | X=x]. A probability is not used to estimate models. Probability estimates come from the model's estimated parameters. The notion of classification need not be involved, and requires specification of an additional function - the loss function. Those who do not specify a loss (utility) function are using one implicitly without knowing it. Probabilities can be used on their own by decision makers. |
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Jun 10 |
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Binary choice model and classification This has nothing to do with academia vs practice. Are you familiar with credit scoring models done in finance? Lift curves in business? |
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Jun 10 |
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Binary choice model and classification I do not agree that most users focus on the classification and not the probability estimates. A 0.5 threshold (and any other) is arbitrary and reflects a lack of incorporation of loss/utility/cost functions. |
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Jun 10 |
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R vs SAS, why is SAS prefered by private companies? Having used SAS for 23 years and S-Plus/R for 22 years I can say that a highly experienced SAS programmer can be highly productive, but that an experienced R programmer can be easily three times as productive. |
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Jun 9 |
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Binary choice model and classification I disagree sharply. The number one goal for the vast majority of problems is to estimate Prob[Y=1], not to do a forced choice between Y=0 and Y=1. And the entire method of maximum likelihood estimation, used to estimate the logistic regression coefficients, is based on this. |
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Jun 7 |
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Binary choice model and classification It is important to distinguish between the nature of Y (e.g., it is a continuous measure, an inherently dichotomous entity, or a classification of an underlying entity (usually information losing)) and the problem to be solved (prediction of the probability of a new Y or classification using X). The widely applicable method of logistic regression is a risk prediction method, which has many advantages over a "classify into a binary Y" method. |
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Jun 7 |
answered | Fisher's exact test for results of Wilcoxon-Mann-Whitney |
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Jun 6 |
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How to split a data set to do 10-fold cross validation Be sure to repeat the entire process 100 times to achieve satisfactory precision. |