Skip to main content
replaced http://stackoverflow.com/ with https://stackoverflow.com/
Source Link

I'm interested in comparing two independent proportions from two samples. The formula for doing so is available in the Internet (e.g. here). So far, so good.

But my main purpose is not to build a confidence interval. Rather I want to assess how big the second proportion has to be to be significant higher than the first proportion (given an alpha level and both sample sizes).

Suppose I conducted a study and found that 80% of 154 respondents used product X. Suppose further that I will do a second study with the same questions and I'm going for n=200 respondents. How big has this second proportion to be, to be signifcantly higher on a 90% alpha level?

Could anyone provide me with the specific formula which is solved for the second proportion? I know there are online calculators or GPower for exactly such purposes, but unfortunately I have to build up theses formula in Excel and thus have to put them in on my own.

(I originally posted on Stack Overflowposted on Stack Overflow, but was told that for statistics I might be better with posting my question here again, so sorry for crossposting!)

I'm interested in comparing two independent proportions from two samples. The formula for doing so is available in the Internet (e.g. here). So far, so good.

But my main purpose is not to build a confidence interval. Rather I want to assess how big the second proportion has to be to be significant higher than the first proportion (given an alpha level and both sample sizes).

Suppose I conducted a study and found that 80% of 154 respondents used product X. Suppose further that I will do a second study with the same questions and I'm going for n=200 respondents. How big has this second proportion to be, to be signifcantly higher on a 90% alpha level?

Could anyone provide me with the specific formula which is solved for the second proportion? I know there are online calculators or GPower for exactly such purposes, but unfortunately I have to build up theses formula in Excel and thus have to put them in on my own.

(I originally posted on Stack Overflow, but was told that for statistics I might be better with posting my question here again, so sorry for crossposting!)

I'm interested in comparing two independent proportions from two samples. The formula for doing so is available in the Internet (e.g. here). So far, so good.

But my main purpose is not to build a confidence interval. Rather I want to assess how big the second proportion has to be to be significant higher than the first proportion (given an alpha level and both sample sizes).

Suppose I conducted a study and found that 80% of 154 respondents used product X. Suppose further that I will do a second study with the same questions and I'm going for n=200 respondents. How big has this second proportion to be, to be signifcantly higher on a 90% alpha level?

Could anyone provide me with the specific formula which is solved for the second proportion? I know there are online calculators or GPower for exactly such purposes, but unfortunately I have to build up theses formula in Excel and thus have to put them in on my own.

(I originally posted on Stack Overflow, but was told that for statistics I might be better with posting my question here again, so sorry for crossposting!)

tidy up
Source Link
Silverfish
  • 23.9k
  • 28
  • 105
  • 206

I have asked this question already here (http://stackoverflow.com/questions/27918883/solving-formula-for-confidence-intervals-on-two-proportions), but was told that for statistics purposes I might be better with posting my question here again. So sorry for crossposting!

Anyway...I would much appreciate your help regarding this:

I'm a little bit stuck (because my math is somehow rusty).

I'm interested in comparing two independent proportions from two samples. The formula for doing so is available in the Internet (e.g. http://www.kean.edu/~fosborne/bstat/06d2pop.htmlhere). So far, so good.

But my main purpose is not to build a confidence interval. Rather I want to assess how big the second proportion has to be to be significant higher than the first proportion (given an alpha-level level and both sample sizes).

Suppose I conducted a study and found that 80% of 154 respondents used poductproduct X. Suppose further that I will do a second study with the same questions and I'm going for n=200 respondents. How big has this second proportion to be, to be signifcantly higher on a 90%-alpha-level alpha level?

Could anyone provide me with the specific formula which is solved for the second proportion? I'm lost. :/

I know there are online calculators or GPower for exactly such purposes, but unfortunately I have to build up theses formula in Excel and thus have to put them in on my own.

Thanks(I originally posted on Stack Overflow, but was told that for your helpstatistics I might be better with posting my question here again, so sorry for crossposting! deschen2)

I have asked this question already here (http://stackoverflow.com/questions/27918883/solving-formula-for-confidence-intervals-on-two-proportions), but was told that for statistics purposes I might be better with posting my question here again. So sorry for crossposting!

Anyway...I would much appreciate your help regarding this:

I'm a little bit stuck (because my math is somehow rusty).

I'm interested in comparing two independent proportions from two samples. The formula for doing so is available in the Internet (e.g. http://www.kean.edu/~fosborne/bstat/06d2pop.html). So far, so good.

But my main purpose is not to build a confidence interval. Rather I want to assess how big the second proportion has to be to be significant higher than the first proportion (given an alpha-level and both sample sizes).

Suppose I conducted a study and found that 80% of 154 respondents used poduct X. Suppose further that I will do a second study with the same questions and I'm going for n=200 respondents. How big has this second proportion to be, to be signifcantly higher on a 90%-alpha-level?

Could anyone provide me with the specific formula which is solved for the second proportion? I'm lost. :/

I know there are online calculators or GPower for exactly such purposes, but unfortunately I have to build up theses formula in Excel and thus have to put them in on my own.

Thanks for your help! deschen2

I'm interested in comparing two independent proportions from two samples. The formula for doing so is available in the Internet (e.g. here). So far, so good.

But my main purpose is not to build a confidence interval. Rather I want to assess how big the second proportion has to be to be significant higher than the first proportion (given an alpha level and both sample sizes).

Suppose I conducted a study and found that 80% of 154 respondents used product X. Suppose further that I will do a second study with the same questions and I'm going for n=200 respondents. How big has this second proportion to be, to be signifcantly higher on a 90% alpha level?

Could anyone provide me with the specific formula which is solved for the second proportion? I know there are online calculators or GPower for exactly such purposes, but unfortunately I have to build up theses formula in Excel and thus have to put them in on my own.

(I originally posted on Stack Overflow, but was told that for statistics I might be better with posting my question here again, so sorry for crossposting!)

Source Link
deschen
  • 581
  • 4
  • 14

Solving formula for confidence intervals on two proportions

I have asked this question already here (http://stackoverflow.com/questions/27918883/solving-formula-for-confidence-intervals-on-two-proportions), but was told that for statistics purposes I might be better with posting my question here again. So sorry for crossposting!

Anyway...I would much appreciate your help regarding this:

I'm a little bit stuck (because my math is somehow rusty).

I'm interested in comparing two independent proportions from two samples. The formula for doing so is available in the Internet (e.g. http://www.kean.edu/~fosborne/bstat/06d2pop.html). So far, so good.

But my main purpose is not to build a confidence interval. Rather I want to assess how big the second proportion has to be to be significant higher than the first proportion (given an alpha-level and both sample sizes).

Suppose I conducted a study and found that 80% of 154 respondents used poduct X. Suppose further that I will do a second study with the same questions and I'm going for n=200 respondents. How big has this second proportion to be, to be signifcantly higher on a 90%-alpha-level?

Could anyone provide me with the specific formula which is solved for the second proportion? I'm lost. :/

I know there are online calculators or GPower for exactly such purposes, but unfortunately I have to build up theses formula in Excel and thus have to put them in on my own.

Thanks for your help! deschen2