Timeline for Why fitting does not find the true best point
Current License: CC BY-SA 3.0
3 events
| when toggle format | what | by | license | comment | |
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| Sep 7, 2015 at 22:46 | comment | added | Glen_b | Because a better fit is possible if the estimate, $b_2$, is allowed to move from being forced to be 0. (NB it's best to have your notation distinguish your estimates from the thing they're estimating.) | |
| Sep 7, 2015 at 15:45 | comment | added | Ben Bolker | because the $a$ parameter is shared between the two groups, so fitting to both groups requires a compromise between the best-fitting values for the two groups ... ? | |
| Sep 7, 2015 at 15:33 | history | asked | Miguel | CC BY-SA 3.0 |