Timeline for How to find P(X > F) in ANOVA F-test?
Current License: CC BY-SA 3.0
19 events
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Nov 6, 2011 at 14:17 | vote | accept | Arvin | ||
Nov 1, 2011 at 13:46 | comment | added | whuber♦ | FWIW, Arvin, formulas for the F distribution are available at Wikipedia. Most people use software or tables :-). But that doesn't matter here: at issue is the concept of working with areas and PDFs to reason about data. | |
Nov 1, 2011 at 10:50 | vote | accept | Arvin | ||
Nov 6, 2011 at 14:17 | |||||
Nov 1, 2011 at 10:49 | comment | added | Arvin | Hmm yes I see what you mean, but yeah, it doesn't make a difference to this question. I'll try to be more careful in the future though! | |
Nov 1, 2011 at 10:43 | answer | added | Ricky | timeline score: 5 | |
Nov 1, 2011 at 8:49 | history | edited | chl | CC BY-SA 3.0 |
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Nov 1, 2011 at 8:18 | history | tweeted | twitter.com/#!/StackStats/status/131284009031438336 | ||
Nov 1, 2011 at 7:58 | comment | added | rolando2 | I realize that this is not the subject of your question, but in the way you have restated your hypothesis, do you notice that you have gone from testing for any statistical connection to presuming a causal connection between the two variables? | |
Nov 1, 2011 at 5:55 | vote | accept | Arvin | ||
Nov 1, 2011 at 7:08 | |||||
Nov 1, 2011 at 5:25 | answer | added | Sasha | timeline score: 1 | |
Nov 1, 2011 at 5:10 | comment | added | Arvin | Ok, thanks for that. Now how do we calculate the area to the right of 3.77? Is there a formula that i'm missing? | |
Nov 1, 2011 at 5:01 | comment | added | Karl | @Arvin - The p-value is the area to the right of 3.77; with PDFs, we only look at areas. | |
Nov 1, 2011 at 4:45 | comment | added | Arvin | Hmm, ok, I think I see. I graphed the F-distribution $F_{3,19}$ on an online graph generator. So is the P value the area under the graph to the right of 3.77 or is it the PDF value of the graph at 3.77? | |
Nov 1, 2011 at 4:29 | history | edited | Arvin | CC BY-SA 3.0 |
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Nov 1, 2011 at 3:38 | history | edited | whuber♦ |
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Nov 1, 2011 at 3:38 | comment | added | whuber♦ | Think about it: the chance that $X$ exceeds 3.77 (the p-value) must be less than the chance that $X$ exceeds 3.1274 (equal to 0.05 by construction). "The probability that 3.1274 is greater than 3.77" does not make any sense. If you're still unclear about this, draw a sketch of the PDF of the F-distribution and highlight the areas under the curve that correspond to (a) the rightmost .05 of the total area and (b) the area to the right of 3.77. | |
Nov 1, 2011 at 3:20 | history | edited | Arvin |
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Nov 1, 2011 at 3:11 | history | migrated | from math.stackexchange.com (revisions) | ||
Nov 1, 2011 at 2:42 | history | asked | Arvin | CC BY-SA 3.0 |