Timeline for Hypothesis testing for mean
Current License: CC BY-SA 3.0
7 events
| when toggle format | what | by | license | comment | |
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| Feb 26, 2015 at 10:55 | answer | added | Glen_b | timeline score: 1 | |
| Nov 10, 2011 at 20:17 | comment | added | Dilip Sarwate | You know that the failure rate $h_A$ of A is smaller than the failure rate $h_B$ of B. Since the failures of B are exponentially distributed with mean $n_0$, we have that $h_B=1/n_0$. Since X is also exponentially distributed,$$h_A=\frac{1}{E[X]}=\frac{1}{m}<h_B=\frac{1}{n_0},$$ that is, $m>n_0$. So if $n_0$ is a known quantity, then the null hypothesis $m\leq m_0$ is trivially false if $m_0\leq n_0$ and untestable if $n_0<m_0$ since samples of B have no information about A. If $n_0$ is not known, test null hypothesis $n_0\leq m_0$ and if you reject it, then reject $m\leq m_0$ also. | |
| Nov 10, 2011 at 8:19 | history | tweeted | twitter.com/#!/StackStats/status/134545789451120641 | ||
| Nov 10, 2011 at 7:39 | history | edited | user88 | CC BY-SA 3.0 |
edited tags; edited title
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| S Nov 10, 2011 at 7:09 | history | suggested | Xi'an | CC BY-SA 3.0 |
lateXing math again
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| Nov 10, 2011 at 6:23 | review | Suggested edits | |||
| S Nov 10, 2011 at 7:09 | |||||
| Nov 10, 2011 at 3:36 | history | asked | RIchard Williams | CC BY-SA 3.0 |