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Jun 13, 2012 at 23:29 vote accept David
Feb 16, 2012 at 15:09 comment added cardinal @David: If this answer has been helpful, you should consider formally accepting it. :)
Feb 14, 2012 at 2:59 comment added David Thank you so much all. Its really good discussion. Finally, we got the estimator $\hat\theta$ is not unbaised.
Feb 14, 2012 at 1:36 history edited Macro CC BY-SA 3.0
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Feb 14, 2012 at 1:29 history edited Macro CC BY-SA 3.0
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Feb 14, 2012 at 1:01 history edited Macro CC BY-SA 3.0
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Feb 14, 2012 at 0:52 comment added cardinal I think that would be my answer, too. Honestly, it makes me suspicious that either (a) the OP hasn't quite stated the problem as intended or (b) the question was poorly thought out in the first place.
Feb 14, 2012 at 0:01 comment added Macro Maybe the answer is that $\hat{\theta}$ is not unbiased because $E(\hat{\theta})$ doesn't exist?
Feb 13, 2012 at 23:54 comment added Macro Good point, cardinal. I was thinking of this in the case where $X$ has an arbitrary distribution but didn't think of the case where there is mass at 0. So, of course, the logic above only applies when $E(1/\overline{X})$ exists.
Feb 13, 2012 at 14:44 comment added cardinal This seems to be a bit of a weird problem since $\mathbb P(\bar X_n = 0) >0$ for all $n$. I've only thought about this for a moment, but navigating around this fact looks difficult at the moment.
Feb 13, 2012 at 4:01 history answered Macro CC BY-SA 3.0