Timeline for How to analyze results of this experiment?
Current License: CC BY-SA 3.0
6 events
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| Oct 23, 2016 at 9:00 | comment | added | RomRom | Then i think you would have to dummy code each of A1, A2... into dummy codes low, medium, high and insert them all into your linear function. i.e If a treatment is low, the dummy will be zero for high and medium and 1 for the low. and if its combination of Low and medium you will have 1 and 1 and zero on high... sorry i can't think of any other way.. | |
| Oct 22, 2016 at 1:13 | comment | added | Milos | No, factors are $A_1, A_2, \ldots, A_6$, and a treatment is a combination of their values, e.g.: [Low $A_1$, Low $A_2$, High $A_3$, Medium $A_4$, Low $A_5$, High $A_6$]. :) | |
| Oct 21, 2016 at 23:56 | comment | added | RomRom | That is: Y= β0+β1A1*A1level +β2A2*A2level..... | |
| Oct 21, 2016 at 23:54 | comment | added | RomRom | Are you saying that your treatments and factors are the same parameters and by treatments you mean different level of each of your factors? (A1; low, medium and high)? if that's the case, can't you create a factor variable for each treatments, call it the level of that treatment (i.e A1 level: A1 none, A1 Low, A1 Medium and A1 high) and then include this as the interaction term in your linear equation?). Moderation is basically the interaction (product term)? this is similar to dummy coding approach again and you will control how your A1 level leading to different Y as opposed to an average Y. | |
| Oct 21, 2016 at 14:16 | comment | added | Milos | Treatments are combinations of low, medium and high values of the factors, chosen in a specific way to order to allow estimation of main effects, two-way interactions and pure quadratic effects of the factors. So, I need to find out how each of the factors $A_1, A_2, \ldots, A_6$ influences $Y$. This is why I don't think that dummy coding treatments would help, or at least, I don't get why it would. :( Can you, please, elaborate more on that and 'moderation'? | |
| Oct 20, 2016 at 22:49 | history | answered | RomRom | CC BY-SA 3.0 |