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Jan 8, 2017 at 0:05 comment added Michael R. Chernick So you get the beta posterior. Was it legitimate to use i/theta as a prior? The exponents are then k-1 and n-k?
Jan 7, 2017 at 22:58 comment added whuber @Michael That wasn't a hint: it is the answer. This is a trivial question.
Jan 7, 2017 at 21:10 history edited gung - Reinstate Monica CC BY-SA 3.0
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Jan 7, 2017 at 21:05 comment added gung - Reinstate Monica This thread has the [self-study] tag, & does present what the OP understands thus far. It meets our standards & can remain open.
Jan 7, 2017 at 14:44 review Close votes
Jan 7, 2017 at 21:10
Jan 7, 2017 at 14:34 history edited Artur
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Jan 7, 2017 at 14:26 vote accept Artur
Jan 7, 2017 at 14:20 comment added Xi'an If this is an assignement, you should have included the self-study tag.
Jan 7, 2017 at 14:12 answer added John K. Kruschke timeline score: 2
Jan 7, 2017 at 12:07 comment added Michael R. Chernick @whuber Can you explain your hint without giving away the answer (assuming that you know it)?
Jan 7, 2017 at 9:39 comment added Artur @Xi'an indeed it looks wierd, but that was given by the assignment: p(theta) ∝ 1/theta
Jan 7, 2017 at 9:37 comment added Artur @MichaelChernick, the data is discrete. The random variable is the numer of patience with no side effects. I am a bit comfused myself about the form of the prior, but that was given by the assignment: p(theta) ∝ 1/theta.
Jan 7, 2017 at 8:36 comment added Xi'an This prior should not be used because the posterior is not defined when $X=n$, which has a positive probability to occur under the Binomial model.
Jan 6, 2017 at 23:11 comment added whuber $\beta = n-k+1$.
Jan 6, 2017 at 23:00 comment added Michael R. Chernick Is your data discrete or continuous? Is the parameter a proportion. I am thinking you may be talking about a situation wher you have a beta posterior and a binomial likelihood. But why does a 1/theta prior enter into it? Is that even a proper prior?
Jan 6, 2017 at 22:43 review First posts
Jan 6, 2017 at 23:11
Jan 6, 2017 at 22:41 history asked Artur CC BY-SA 3.0