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Jan 14, 2021 at 16:57 comment added equaeghe @JeremyDorner: First bring the outside ratio of Gamma functions inside. Then you get $s\cdot\sqrt{\frac{\frac{n-1}{2}\cdot\Gamma(\frac{n-1}{2})^2}{\Gamma(\frac{n}{2})^2}-1}$. Apply Stirling's approximation <en.wikipedia.org/wiki/Gamma_function#Stirling's_formula> to both Gamma function values and simplify.
Jan 13, 2021 at 10:06 comment added Jeremy Dorner @equaeghe bit of a long shot, but is there a derivation for that? I tried applying Stirling's approximation but wasn't able to derive it.
Jul 18, 2019 at 5:01 comment added Syrtis Major For those who want a simple form, $s/\sqrt{2(n-1)}$ is a good approximation at a few percent level.
Apr 13, 2017 at 12:44 history edited CommunityBot
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Feb 4, 2017 at 16:18 comment added Harvey Motulsky Probably worth pointing out that s (computed in @Macro's answer is sometimes referred to as the standard error of the sample standard deviation.
Nov 3, 2016 at 18:57 comment added equaeghe The Gamma function is hard to calculate for non-small values of $n$. Applying Stirling's approximation, I get $s\cdot\sqrt{\mathrm{e}\cdot(1-\frac{1}{n})^{n-1}-1}$, which is computationally feasible as well as a bit more compact expression-wise.
Aug 9, 2016 at 19:10 comment added danijar Did you forget to square the distances in the first formula?
May 29, 2012 at 2:39 history edited Macro CC BY-SA 3.0
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May 16, 2012 at 21:55 comment added whuber +1 It's nice to see not only a better reply come along after almost two years, but a reply that provides more useful detail than the references elsewhere in this thread.
May 16, 2012 at 17:05 history edited Macro CC BY-SA 3.0
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May 16, 2012 at 1:23 history edited Macro CC BY-SA 3.0
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May 16, 2012 at 0:20 history answered Macro CC BY-SA 3.0