Timeline for uniform pareto system error
Current License: CC BY-SA 4.0
9 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| May 10, 2018 at 8:12 | vote | accept | CommunityBot | ||
| May 10, 2018 at 0:29 | answer | added | Ben | timeline score: 1 | |
| May 8, 2018 at 17:38 | comment | added | user207460 | So the error is not the border of integration, but I have to add an indicator function in the likelihhod? Could you please state the correct formula? | |
| May 8, 2018 at 16:58 | comment | added | whuber♦ | The value of the Pareto PDF for any $x_i \lt k$ is, by definition, zero. You haven't accounted for that in your formula for the distribution. Your integral formula cannot be correct because it doesn't depend on $x$ at all. | |
| May 8, 2018 at 16:13 | comment | added | user207460 | I fixed this problem by taking the integral from $max(x_1,\dots,x_n, k )$ intsead of k to $\infty$, but why is it so and why is the lower bound not simply $k$? | |
| May 8, 2018 at 15:59 | comment | added | user207460 | @whuber I obtained this expression by formula from wikipedia and just plugged in prior and a-priori-density, but I have seen that the correct expression should be the one on the right and this is not equal to my result, what did I do wrong? | |
| May 8, 2018 at 11:12 | comment | added | whuber♦ | Please explain how you obtained your expression for $p(\theta\mid x),$ since evidently it doesn't depend on $x$ at all! | |
| May 8, 2018 at 9:24 | review | First posts | |||
| May 8, 2018 at 9:39 | |||||
| May 8, 2018 at 9:21 | history | asked | user207460 | CC BY-SA 4.0 |