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Sep 10, 2018 at 18:00 history closed whuber Needs details or clarity
Sep 10, 2018 at 17:57 history edited Itee Louis CC BY-SA 4.0
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Jul 6, 2018 at 17:08 history undeleted Itee Louis
Jul 6, 2018 at 13:48 history deleted Itee Louis via Vote
Jul 5, 2018 at 17:20 comment added Itee Louis Dear Juho Kokkala,wolfies. I have solved my question. you can checked again. Note:matrix X1 and X2 are Independent.
Jul 5, 2018 at 17:19 history edited Itee Louis CC BY-SA 4.0
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Jul 5, 2018 at 15:35 comment added wolfies You have not stated the relationship between $X_1$ and $X_2$
Jul 5, 2018 at 11:27 history reopened whuber
Jul 5, 2018 at 11:08 comment added Juho Kokkala This may help: stats.stackexchange.com/editing-help#LaTeX (though based on a quick glance I think the question itself is somewhat unclear - how do the "sample covariance matrices" arise or how they are related to the random vectors $\mathbf{X}_1$ and $\mathbf{X}_2$?
Jul 5, 2018 at 10:42 history edited Itee Louis CC BY-SA 4.0
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Jul 5, 2018 at 8:52 comment added Itee Louis Dear Juho Kokkala, Sorry i use this site for the first time. I do not know how to write symbols or equations.
Jul 5, 2018 at 8:45 comment added Juho Kokkala Please edit the information into the text rather than by adding a picture
Jul 5, 2018 at 8:10 history edited Itee Louis CC BY-SA 4.0
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Jul 5, 2018 at 7:39 review Reopen votes
Jul 5, 2018 at 11:27
Jul 5, 2018 at 7:29 history edited Itee Louis
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Jul 5, 2018 at 7:24 comment added Itee Louis Dear Juho Kokkala, I'm sorry for the unclear question. I have solved my question. you can checked again.
Jul 5, 2018 at 7:20 history edited Itee Louis CC BY-SA 4.0
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Jul 4, 2018 at 12:04 comment added Juho Kokkala The covariance cannot be determined from this information. Presumably in the case you are interested in, you know something more about the dependence than just "not independent" - it might be helpful to explain how these distributions arise
Jul 4, 2018 at 10:42 history closed Juho Kokkala
kjetil b halvorsen
whuber
Needs details or clarity
Jul 4, 2018 at 9:31 comment added Itee Louis Dear kjetil b halvorsen, I mean in general form of Cov(X,Y) = E(XY) -E(X)E(Y) when X,Y has F-distribution. Does not mean covariance of data.
Jul 4, 2018 at 9:26 comment added kjetil b halvorsen With the information you have given, the only we can say is that the covariance is a number somewhere between $-\infty$ and $\infty$. So you need to give us some more. First, please tell us in which context your question arises.
Jul 4, 2018 at 8:28 comment added Itee Louis Dear wolfies, Which part do not you not understand my question ??.
Jul 4, 2018 at 7:54 comment added wolfies ???????????????
Jul 4, 2018 at 7:37 comment added Itee Louis Dear wolfies, In case, X and Y are independent random variable. I know joint pdf of X and Y. But in this case, X and Y are not independent, So I can not know joint pdf of X and Y.
Jul 4, 2018 at 7:14 review Close votes
Jul 4, 2018 at 10:43
Jul 4, 2018 at 6:43 history edited Jan Kukacka CC BY-SA 4.0
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Jul 4, 2018 at 6:29 comment added wolfies What is the joint pdf of $X$ and $Y$? Absent that, how long is a piece of string.
Jul 4, 2018 at 6:13 review First posts
Jul 4, 2018 at 6:43
Jul 4, 2018 at 6:10 history asked Itee Louis CC BY-SA 4.0