Timeline for Feller shoe-matching problem
Current License: CC BY-SA 4.0
7 events
| when toggle format | what | by | license | comment | |
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| Sep 10 at 13:12 | history | edited | kjetil b halvorsen♦ | CC BY-SA 4.0 |
deleted 34 characters in body
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| Sep 30, 2018 at 5:42 | vote | accept | Win_odd Dhamnekar | ||
| Sep 28, 2018 at 11:26 | comment | added | Win_odd Dhamnekar | Author had given correct answer. My answer was wrong. Now I have provided the correct answer by editing my question. | |
| Sep 22, 2018 at 3:05 | comment | added | BruceET | Some misunderstanding here. Feller's answer is correct. Your view would have more weight if accompanied by a combinatorial argument in addition to claims of correctness. | |
| Sep 22, 2018 at 2:45 | comment | added | Win_odd Dhamnekar | Question is asking probability of at least one pair of shoes in the selected four number of shoes.So this is equal to probability of one pair of shoes and probability of two pair of shoes in the selection of four shoes out of ten pairs of shoes. I have posted exactly the same answer.So my answer is correct.Author might have forgotten to consider the probability of success and failure. | |
| Sep 22, 2018 at 0:49 | history | edited | BruceET | CC BY-SA 4.0 |
added 5 characters in body
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| Sep 22, 2018 at 0:05 | history | answered | BruceET | CC BY-SA 4.0 |