Timeline for Formal definition of random assignment
Current License: CC BY-SA 3.0
18 events
when toggle format | what | by | license | comment | |
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Feb 24, 2017 at 15:54 | history | edited | mdewey |
Replaced randomization with random-allocation
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Sep 21, 2012 at 14:08 | vote | accept | user697473 | ||
Sep 17, 2012 at 21:41 | comment | added | user697473 | @whuber -- thanks. That was a typo. I fixed it. | |
Sep 17, 2012 at 21:40 | history | edited | user697473 | CC BY-SA 3.0 |
Fixed typo (i.e., changed \mathbf{z} to \mathbf{Z}).
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Sep 17, 2012 at 21:05 | comment | added | whuber♦ | I believe @mpiktas was really wondering what $\mathbf{z}$ meant (as opposed to $\mathbf{Z}$): I suspect it's a typographical error. | |
Sep 17, 2012 at 19:17 | answer | added | Charlie | timeline score: 2 | |
Sep 17, 2012 at 18:01 | history | tweeted | twitter.com/#!/StackStats/status/247757074501623808 | ||
Sep 17, 2012 at 17:52 | history | edited | user697473 | CC BY-SA 3.0 |
Replaced article link with link to a better-looking PDF of the same article
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Sep 17, 2012 at 17:31 | comment | added | user697473 | @mpiktas, $Z_i$ is the $i$th element of $\mathbf{Z}$. $\mathbf{Z}, \mathbf{c},$ and $\mathbf{c'}$ are vectors of zeroes and ones; all of these vectors have the same length. $\iota$ is a "counting vector" -- all ones -- so $\iota^T\mathbf{c}$ is just the number (i.e., the sum) of ones in $\mathbf{c}$. And a similar definition holds for $\iota^T\mathbf{c'}$. I hope that this helps. | |
Sep 17, 2012 at 17:28 | comment | added | user697473 | @StasK, thanks for the suggestion. I added a link to the original post. | |
Sep 17, 2012 at 17:27 | history | edited | user697473 | CC BY-SA 3.0 |
Added link to article mentioned in post
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Sep 17, 2012 at 17:03 | comment | added | StasK | @user697473, please give a link to the full text of the paper you cite. Respect the time of the people answering this; or at least assume they will be too lazy even to Google it (I certainly was). | |
Sep 17, 2012 at 17:02 | answer | added | StasK | timeline score: 8 | |
Sep 17, 2012 at 12:59 | answer | added | Michael R. Chernick | timeline score: 3 | |
Sep 17, 2012 at 12:39 | comment | added | mpiktas | Please explain the definitions in the second paragraph more clearly, i.e. whats is $\mathbf{z}$, $\mathbf{c}$ and $\mathbf{c}'$? | |
Sep 17, 2012 at 12:38 | comment | added | Peter Flom | No. If you rule out some assignment vectors a priori you no longer have random assignment, strictly speaking. | |
Sep 17, 2012 at 12:37 | history | edited | mpiktas | CC BY-SA 3.0 |
edited title
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Sep 17, 2012 at 12:18 | history | asked | user697473 | CC BY-SA 3.0 |