I'm attempting to calculate the studentized residuals on a (equality) constrained least-squares regression for outlier detection. However, i'm a little uncertain on how to calculate the leverages, $h_i$, which is the diagonal of the "hat-matrix", $H$.
In the ordinary least squares case (without linear constraints), this matrix is computed as
$$ H = ( X^T X)^{-1}X^T y \quad \quad \quad (1) $$$$ H = X\left(X^T X\right)^{-1}X^T \quad \quad \quad (1) $$
Where $X$ is the design matrix and $y$ is the variable to be explained. The constrained least-squares regression i'm attempting to do is the following:
$$ \left[ \begin{array}{c} \hat{\beta} \\ \hat{\lambda} \end{array} \right] = \left[ \begin{array}{cc} 2 X^T X & C^T \\ C & 0 \end{array} \right]^{-1} \left[ \begin{array}{c} 2 X^T y \\ d \end{array} \right] $$
where $X$ is again the design matrix, $y$ the variable to be explained and $C$ is the restriction matrix such that
$$ C \beta = d. $$
$\lambda$ is in this case the lagrange multipliers. My Question is then, what is the "hat"-equivalent matrix for this type of regression? Will the formulation in $(1)$ hold? My quess is no, since you are adding additional information to the regression. For instance, if you added 0-restrictions to some of the columns, you might as well have excluded them from the design matrix, in which case the leverages would change.