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Jul 10, 2019 at 12:04 comment added Michael So $\Sigma$ here is the orthogonal projection onto the orthogonal complement of $(1,...,1)'$ (say $\sigma^2 = 1$). Then $\Sigma = \Sigma^+$. The pseudo-determinant of $2 \pi \Sigma$ is $(2 \pi)^{n-1}$. Where does $n$ come from?
Jul 10, 2019 at 4:34 history answered user158565 CC BY-SA 4.0