Timeline for ¿How to compaire nested logit models using anova in R?
Current License: CC BY-SA 4.0
4 events
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| Apr 26, 2020 at 20:12 | comment | added | StupidWolf | Hi @JuanLuisAndiónTápiz, more or less yes. | |
| Apr 26, 2020 at 12:42 | comment | added | Juan Luis Andión Tápiz |
Then, looking the deviance difference from my models 18.664 and knowing that when I execute the Chi-square with anova this value is Pr(>Chi) = 0.0003 ¿Can we conclude that the study variables has explanatory power on the health-status?
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| Apr 25, 2020 at 22:29 | vote | accept | Juan Luis Andión Tápiz | ||
| Apr 25, 2020 at 22:07 | history | answered | StupidWolf | CC BY-SA 4.0 |