Timeline for Is there any algorithm combining classification and regression?
Current License: CC BY-SA 4.0
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Nov 17, 2020 at 11:42 | comment | added | Frank Harrell | For some tasks, reporting continuous predicted values or estimated probabilities of class membership is all that's needed, and you defer the decision to a decision maker who has her own internal utiities. Otherwise if you define a utility/cost/loss function e.g. quantify the relative harms of classifying a true category A as a B and of classifying a true category B as an A you can pick the category that minimizes expected harm/cost, i.e., that maximizes expected utility. | |
Nov 17, 2020 at 8:04 | comment | added | yuri | how would this ''utility function'' look like? the dataset was labeled with landmarks coordinates and 0/1 occlusion status. the dataset supplier is assuming landmark classification. the link that you provided isn't directly treating ML for image analysis. but I should confess one can learn a lot from it. | |
Nov 16, 2020 at 13:28 | comment | added | Frank Harrell | No it's not obvious that it is a classification problem, and forced-choice classification is misleading when there is a gray zone, i.e., intermediate probability of class membership that should result in "no decision, get more data". Once you develop optimum prediction you can combine that with a utility function to get an optimum decision, avoiding the need to classify. | |
Nov 16, 2020 at 13:13 | comment | added | yuri | I have to detect facial landmarks from face images and classify each detected landmark as occluded or not occluded. so landmark detection is a regression problem that maps the image space to the landmarks coordinate space and the landmark classification is obviously a classification problem. | |
Nov 16, 2020 at 12:11 | comment | added | Frank Harrell | It's hard to understand why something as complicated as these solutions is needed. It's best to analyze the rawest form of the data. Classification (if really needed; a case was not made for it) can be done on the basis of the continuous predictions once the utility function is defined. | |
Nov 16, 2020 at 8:22 | history | edited | yuri | CC BY-SA 4.0 |
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Nov 16, 2020 at 8:01 | history | edited | yuri | CC BY-SA 4.0 |
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Nov 12, 2020 at 7:17 | history | edited | yuri | CC BY-SA 4.0 |
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Nov 11, 2020 at 10:21 | review | Late answers | |||
Nov 11, 2020 at 11:15 | |||||
Nov 11, 2020 at 10:05 | history | answered | yuri | CC BY-SA 4.0 |