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Jul 21, 2021 at 12:00 history tweeted twitter.com/StackStats/status/1417816655422533634
Jul 21, 2021 at 10:00 comment added Christian Hennig The p-value may happen to be equal or approximately equal to a Bayesian probability that H0 is true given a certain prior, but still according to frequentist logic it is something essentially different.
Jul 21, 2021 at 9:58 comment added Christian Hennig Note that in frequentist analysis the parameters and hypotheses are not random variables, so it's technically wrong to write $P(data|H0)$, because this suggests that it's a conditional probability based on the random variable H0 taking a certain value. It's more correct to write $P_{H0}(data)$, as this says that it's the unconditional probability of the data assuming that H0 is true. Consequently no frequentist analysis will give you a probability that H0 is true (the p-value is definitively not such a probability), because such a probability is not defined in frequentism.
Jul 21, 2021 at 8:04 vote accept jcp
Jul 21, 2021 at 7:32 answer added Tim timeline score: 1
Jul 21, 2021 at 0:00 history edited jcp CC BY-SA 4.0
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Jul 20, 2021 at 23:17 history asked jcp CC BY-SA 4.0