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Apr 7, 2022 at 17:41 comment added Sextus Empiricus You could add $S^2$ as well but then you are gonna relate to assuming some specific type of probability distribution, which you wanted to avoid.
Apr 7, 2022 at 17:39 comment added Sextus Empiricus @Manuel in my answer the $S^2$ is not included as observation. We just have $\mathcal{L}(\mu , \sigma^2 | \bar X)$
Apr 7, 2022 at 13:11 comment added Manuel I am struggling to give $\mathcal{L}(\mu , \sigma^2 | \bar X, S^2)$ any idea o how should that be?
Apr 6, 2022 at 16:55 vote accept Manuel
Apr 6, 2022 at 16:53 comment added Manuel This is what i need. It did take me some time to realize that $\mathcal{L}(\mu | \bar X) = f( \bar X | \mu)$. The related question was quite helpful. Thanks!
Apr 6, 2022 at 14:50 history edited Sextus Empiricus CC BY-SA 4.0
added 69 characters in body
Apr 6, 2022 at 14:29 history answered Sextus Empiricus CC BY-SA 4.0