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May 21 at 8:09 history edited Raul CC BY-SA 4.0
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May 21 at 8:08 comment added Raul Absolutely right. I was being a bit sloppy in the notation. I have changed it to SD(s) as this notation was used in the original post. Many thanks for the explanation of the asymptotic behavior and the clear graph.
May 21 at 8:01 history edited Raul CC BY-SA 4.0
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May 20 at 12:43 review First answers
May 20 at 12:47
May 20 at 12:41 comment added whuber Welcome to CV, Raul. Because we look for support and explanations of claims, I have made some small edits to your original post. Please feel free to modify them if you wish.
S May 20 at 12:40 review First answers
May 20 at 12:41
S May 20 at 12:40 history edited whuber CC BY-SA 4.0
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May 20 at 12:28 history undeleted whuber
May 20 at 12:22 history deleted Sycorax via Vote
May 20 at 11:33 review Low quality posts
May 20 at 12:26
May 20 at 11:33 comment added utobi Maybe there is a typo in your text, $\sigma$ is a constant thus it's variance is 0.
May 20 at 10:21 review Late answers
May 20 at 11:10
May 20 at 10:05 history edited Raul CC BY-SA 4.0
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S May 20 at 10:05 review First answers
May 20 at 11:33
S May 20 at 10:05 history answered Raul CC BY-SA 4.0