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Mar 20, 2014 at 20:08 vote accept Charlie Parker
Mar 20, 2014 at 19:54 answer added Marc Claesen timeline score: 3
Mar 20, 2014 at 19:46 history edited Charlie Parker CC BY-SA 3.0
made my question better english
Mar 20, 2014 at 19:41 comment added Charlie Parker Don't worry, I think I also wrote the question a little weirdly, let me write it clearer, I agree its not the best wording I could have chosen. You should try look for a clarification before writing an angry comment and down voting though :P I was so sad for a second hehe But I understand the misunderstanding. I'll improve my question.
Mar 20, 2014 at 19:39 history edited user603 CC BY-SA 3.0
deleted 1 characters in body
Mar 20, 2014 at 19:39 comment added user603 thanks for the clarification. I see now: I had read the equations a bit too fast and clearly not paid attention to the surrounding text.
Mar 20, 2014 at 19:36 comment added Charlie Parker @user603 in the case of no offset, for support vectors we have $y^{(i)} \theta \cdot x^{(i)} = 1$ (I said no slack and then later asked whats going on with slack). If $\theta = \sum^n_{i=1} \alpha_i y^{i} x^{(i)}$ then the constrain becomes: $y^{(i)} \sum^n_{i=1} \alpha_i y^{i} x^{(i)} \cdot x^{(i)} = 1$. Which is what I wrote. For support vectors we can change the inequality to an equality because its a support vector. There is nothing wrong about what I wrote.
Mar 19, 2014 at 21:51 history asked Charlie Parker CC BY-SA 3.0