Timeline for Help me calculate how many people will come to my wedding! Can I attribute a percentage to each person and add them?
Current License: CC BY-SA 3.0
8 events
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| Apr 15, 2014 at 20:18 | comment | added | whuber♦ | This is a wonderful example of an estimator that exists in theory but seems unusual in practice (until you look for this sort of thing): given any set of data, it returns a predetermined number (80% in this case). It is easy to compute, very inexpensive (data collection costs can be reduced to zero) and has zero variance. It is Bayes (for an atomic prior) and admissible. There will still be nagging questions about its bias and consistency that can be difficult to address and won't go away by avoiding a "detailed analysis." | |
| Apr 14, 2014 at 14:38 | comment | added | JTP - Apologise to Monica | @Juho - that may be. I am in the US and in my recent example, it was a destination wedding for about half the invitees, i.e. wedding was in bride's hometown. I wonder what cultural differences would impact turnout, but I suspect you are right. | |
| Apr 14, 2014 at 13:52 | comment | added | Juho Kokkala | This figure might be culture-dependent. | |
| Apr 14, 2014 at 4:20 | comment | added | Behacad | Thank you! One concern is that people will be coming from all over and from varying distances. Some quite far, others just down the street. | |
| Apr 13, 2014 at 20:13 | history | edited | JTP - Apologise to Monica | CC BY-SA 3.0 |
added 43 characters in body
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| Apr 13, 2014 at 19:51 | history | edited | Nick Stauner | CC BY-SA 3.0 |
spelling, grammar, punctuation, clarity, apology removal
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| Apr 13, 2014 at 19:46 | review | First posts | |||
| Apr 13, 2014 at 19:51 | |||||
| Apr 13, 2014 at 19:30 | history | answered | JTP - Apologise to Monica | CC BY-SA 3.0 |