Timeline for Singular Value Decomposition more columns than rows
Current License: CC BY-SA 3.0
4 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| May 6, 2014 at 15:57 | comment | added | Brian Borchers | $\Sigma$ is an $m$ by $n$ diagonal matrix, with possibly nonzero singular values in $\Sigma_{1,1}$ through $\sigma_{m,m}$, but the singular values for $m+1$, $\ldots$, $n$ are all considered to be 0 (there's no place to put these zeros in the $m$ by $n$ matrix $\Sigma$.) | |
| May 6, 2014 at 14:57 | vote | accept | joidegn | ||
| May 6, 2014 at 14:54 | comment | added | joidegn | So the singular values in $\Sigma$ are 0? That would make some sense. Now I know what happens. Can you explain to me or point me to somewhere where I can learn why that happens? | |
| May 6, 2014 at 13:09 | history | answered | Brian Borchers | CC BY-SA 3.0 |