I am reading and trying to learn about the probability integral transform and some of its uses. From the CV question PIT on a sample with m bins, and KS test used to estimate a good value for m, the probability integral transform of random variable $X$ with size $n$ looks very simple:
$$U_{i} = \frac{R_{i}}{n+1}$$
where $R_{i}$ is the rank of the $i^{\text{th}}$ observation in $X$.
I can see where $U$ is uniformly distributed, but in Quantlbex's answer, they write "By construction the distribution of the transformed variables is uniform between 0 and 1."
My doubtlessly naïve question is: shouldn't that be "uniform between $\frac{1}{n+1}$ and $\frac{n}{n+1}$?" Or do we simply say "uniform between 0 and 1" because those are the limiting bounds for arbitrarily high $n$?