"John is taking an algebra and a calculus class. The probability that he will pass algebra is 0.57 and the probability he passes calculus is 0.68. The probability he passes calculus given he passes algebra is 0.72, and the probability that he passes calculus given he doesn't pass algebra is 0.45. What is the probability he passes algebra given he passes calculus."
My approach:
$$P(C|A)\cdot P(A) = P(A \cap C)$$
Then $\dfrac{P(A\cap C)}{P(C)} = 0.6035$,
but this is incorrect according to the professor, and that the answer should be 0.6796
Can anyone explain this? Thank you in advance!