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I would like to ask about the meaning of such notations in general. For example, $$ \mathbb{E}_{(\mathbf{u}, \mathbf{\sigma}, \mathbf{Y}_0)\sim N(0,1)\otimes \mu_D\otimes N(0,1)}\left[ e^{\mathbf{\sigma} t}\mathbf{Y}_0\mathbf{u}\right] $$ where $\mathbf{Y}_0$ is a column vector, $\mu_D$ is a probability measure with a compact support. But the author does explain what is $\mathbf{u}$ here. How to write it in integral?

Is it $$ \mathbb{E}_{(\mathbf{u}, \mathbf{\sigma}, \mathbf{Y}_0)\sim N(0,1)\otimes \mu_D\otimes N(0,1)}\left[ e^{\mathbf{\sigma} t}\mathbf{Y}_0\mathbf{u}\right]=\int e^{\mathbf{\sigma} t}\mathbf{Y}_0\mathbf{u} d\mu_D? $$

I think that means some random variables follow these distributions and take expectations with respect to them. But the author also writes $$ \mathbb{E}_{(\mathbf{u}, \mathbf{\sigma}, \mathbf{Y}_0)\sim N(0,1)\otimes \mu_D\otimes N(0,1)}\left[ e^{\mathbf{\sigma} t}\mathbf{u}^2 \right] $$ There is no $\mathbf{Y}_0$ but why takes expectation w.r.t. measure of $N(0,1)$?

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    $\begingroup$ Some context would help. Which paper? Please edit to add a complete citation & link. $\endgroup$
    – Sycorax
    Commented May 19, 2022 at 23:13

1 Answer 1

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$$\mathbb{E}_{(\mathbf{u}, \mathbf{\sigma}, \mathbf{Y}_0)\sim N(0,1)\otimes \mu_D\otimes N(0,1)}\left[ e^{\mathbf{\sigma} t}\mathbf{Y}_0\mathbf{u}\right]=\int\int\int e^{\mathbf{\sigma} t}\mathbf{Y}_0\mathbf{u}\,\text d N(0,1)(\mathbf{u})\,\text d \mu_D(\sigma)\,\text d N(0,1)(\mathbf{Y}_0)$$ except that the$$\text d N(0,1)(\mathbf{Y}_0)$$clashes with the fact that $\mathbf{Y}_0$ is a vector.

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  • $\begingroup$ measures induced by the corresponding distributions $\endgroup$
    – Xi'an
    Commented May 22, 2022 at 17:30

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