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I'm trying to figure out how to interpret the ftest in 1.2(iv) of the attached sheet. What is the alternative hypothesis being assumed, and what is the null hypothesis being assumed?

Is the interpretation here that, given the t-value from the F-test, there is a chance that this value is not the real mean? Null Hypothesis question

An online T calculator seems to show that there is about a 10% chance of seeing a value smaller than -.933, and approx 10% chance of seeing a value greater than .933, standard errors from the mean.

Cumulative Probability calc

Doesn't this mean that there is more than a 10% chance that the proposed value of .1 is the right value, and that we should reject the null?
Thanks.


You're correct, I did mix up the null and alternative. In addition, the formula from the notes shows the null is the subtracted value in the numerator which would have tipped me off if i saw it earlier.

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  • $\begingroup$ Also extrapolating from iii, it appears that the value .1 falls within our 95% confidence interval for the true mean of b0. So how do we fail to reject the null? This isn't a test of whether a change is significant, in which case I would understand failure to reject the null; it's a test of whether a value is probable. $\endgroup$
    – Info5ek
    Commented Feb 9, 2014 at 6:57
  • $\begingroup$ If you want an answer to the question in your comment, either add it to your question (via an edit), or post a new question. $\endgroup$
    – Glen_b
    Commented Feb 9, 2014 at 8:06

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You've mixed up the null and alternative hypotheses. In this case, the null hypothesis is that $\alpha = 0.1$. Since the P-value is greater than 0.05, we do not reject it.

This is just a variation on the usual theme in hypothesis testing in regression. Normally, when we test whether a coefficient is statistically significant, the (generally unstated) null hypothesis is that the value is zero. In this case, the null hypothesis is that the value is some other fixed value. The procedure is still essentially the same.

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