14
$\begingroup$

I'm throwing here the problem as I received it.

I have two random variables. One of which is continuous (Y) and the other one which is discrete and will be approached as ordinal (X). I put below the plot I received together with the query.

enter image description here

The person who send me the data wants to measure the strength of the association between X and Y. I'm looking for ideas that would not come front loaded with assumptions about what process generated the data. Note that this is not about finding a non parametric way to test the strength of the relationship (as in bootstrap) but about finding a non parametric way to measure it.

On the other hand, efficiency is not an issue since there is a lot of data points.

$\endgroup$
2
  • $\begingroup$ Do by "nonparametric" you mean here that no computation of the mean or the variance is allowed? $\endgroup$
    – ttnphns
    Jun 13, 2014 at 19:50
  • $\begingroup$ Two comments on this: 1. the plot would benefit greatly from hexagonal binning. 2. It's perplexing to think of a bootstrap as testing the strength of a relationship in a non-parametric way. How can we test the strength of a relationship without specifying the way to measure it? $\endgroup$
    – AdamO
    Dec 22, 2022 at 5:16

3 Answers 3

12
$\begingroup$

By definition, ordinal scale is the gauge wherein the true distances between notches 1 2 3 4 is unknown. It is like you are seening a ruler under drugs/alcohol. The true distances can be any. It could be 1 2 3 4 or 1 2 3 4 or whatever. We cannot compute a statistic - such as a correlation - unless decide on the distances, fix them.

One reasoning can be as follows. Since our measuring scale, the gauge, is distorted in an unknown monotonic way, we cannot believe in data values. Only the order of their magnitudes is trustworthy. Without further harness of brain, declare order to be the value. Thus, we replace the observed distribution by uniform distribution, the ranks. After that, may compute association coefficient, say, Pearson $r$. That will be Spearman $rho$, as we know. Pearson $r$ measures the strength of linear association. Ranking the variables was a trick to linearize that portion of monotonic relationship that is attributed to the distributions not having been uniform initially. Thus, Spearman $rho$ is the measure of such monotonicity in the relationship which can be converted to linearity under the action of uniforming the marginal distributions. In the OP question, only one of the two variables is ordinal (and the second is continuous). So, there is no need, generally, to rank both variables. May just rank the ordinal one and then compute $r$.

Another approach, alternative to ranking (uniforming), may be optimal scaling of the ordinal variable. Optimal scaling is an iterative procedure with the goal to find such distances on the ordinal scale - i.e. find such monotonic transformation of it - so that linear $r$ between the variables is maximized as possible. While ranking approach is based on premise "true scale corresponds to data having uniform distribution", optimal scaling approach is based on premise "true scale corresponds to data having maximal linear $r$". Optimal scaling can be done in categorical regression (CATREG). However, categorical regression requires that the other input variable be discrete (not necessarily ordinal) and so if it is continuous having many unique values it will have to be arbitrarily binned by you.

There are other approaches as well. But in any way, we transform the ordinal scale monotonically "so as to..." (some assumption or some goal), because ordinal scale is distorted to us in an unknown way. Radically another decision would be to "sober up" first and decide that it is either not distorted (i.e. it is interval), or distorted in a known way (is nonequiinterval), or is nominal.

Some asymmetric approaches may include ordinal regression of the ordinal variable by the other (interval/continuous) one. Or linear regression of that latter by the ordinal one, with the model where the predictor is taken as polynomial contrast (that is, entered as b1X + b2X^2 + b3X^3,...). The weakness of these approaches is that they are asymmetric: one variable is dependent, the other is independent.

$\endgroup$
1
  • $\begingroup$ thanks; very good idea, to compute the ranks on only one of the variable. $\endgroup$
    – user603
    Jun 14, 2014 at 9:15
7
$\begingroup$

Is there any reason which Spearman's rank-order correlation coefficient (a nonparametric measure of monotonic association) would not suffice? Is monotonicity too "front loaded?" There's a 'shortcut' formula, valid when there are no ties, based on differences ($d_{i} = x_{i} - y_{i}$) in independently generated ranks ($x_{i}$ and $y_{i}$) for your variables:

$$r_{\text{S}} = 1-\frac{6\sum_{i=1}^{n}{d^{2}_{i}}}{n\left(n^{2}-1\right)}$$

If there are ties, rank each variable separately, and calculate Pearson's $r$ using the ranks to calculate $R_{\text{S}}$

If monotonicity is too stringent an assumption, I wonder if approaches based on maximal information, such as that proposed by Reshef (2011, 2013), which do not even assume functional relationships between $X$ and $Y$ might be more along the lines of what you are looking for?


References
Reshef, D., Reshef, Y., Finucane, H., Grossman, S., McVean, G., Turnbaugh, P., Lander, E., Mitzenmacher, M., and Sabeti, P. (2011). Detecting novel associations in large data sets. Science, 334(6062):1518–1524.

Reshef, D., Reshef, Y., Mitzenmacher, M., and Sabeti, P. (2013). Equitability analysis of the maximal information coefficient, with comparisons. arXiv, August 14.

$\endgroup$
1
  • $\begingroup$ Both look like very good ideas. In fact, the two approaches you propose even complement one another. I will leave the question open still a little while. $\endgroup$
    – user603
    Jun 13, 2014 at 16:35
0
$\begingroup$

Two methods discussed in Longitudinal Data Analysis by Diggle et al. are splines and Gaussian Kernel methods.

Splines are an excellent tool for analyzing associations between quasi-continuous variables and other variables. The specific advantage of splines is that, by increasing the polynomial degree, or the number of knots, you can fit increasingly complex trendlines, up to the point of even a saturated model treating each quasi-continuous response as a value. In reasonably large datasets, the spline specifications can be chosen in an automated way using BIC or cross-validation. The cubic smoothing spline in particular is well explored and often utilized. In the end, the result is an easily interpretable generalized trend line relating the two variables.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge that you have read and understand our privacy policy and code of conduct.

Not the answer you're looking for? Browse other questions tagged or ask your own question.