My understanding is that prcomp
and princomp
work off the dataset itself (row of observations, across variables in the columns). Is there a function that will run a principal component analysis directly off a correlation or covariance matrix, without having the "raw" dataset?
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3$\begingroup$ You just may do singular-value or eigen-value decomposition of the matrix, to get eigenvalues and eigenvectors (and then compute loadings out of the two). But without casewise data you won't get component scores, of course. $\endgroup$– ttnphnsJul 15, 2014 at 20:39
1 Answer
You can use eigen()
. For example:
> set.seed(3)
> x <- matrix(rnorm(18), ncol=3)
> x
[,1] [,2] [,3]
[1,] 1.2243136 -0.48445511 0.9006247
[2,] 0.1998116 -0.74107266 0.8517704
[3,] -0.5784837 1.16061578 0.7277152
[4,] -0.9423007 1.01206712 0.7365021
[5,] -0.2037282 -0.07207847 -0.3521296
[6,] -1.6664748 -1.13678230 0.7055155
> prcomp(x)
Standard deviations:
[1] 1.0294417 0.9046837 0.4672911
Rotation:
PC1 PC2 PC3
[1,] -0.84047203 -0.53902142 0.05534150
[2,] 0.53878561 -0.84219645 -0.02037687
[3,] -0.05759199 -0.01269102 -0.99825954
> eigen(cov(x))
$values
[1] 1.0597501 0.8184527 0.2183610
$vectors
[,1] [,2] [,3]
[1,] 0.84047203 0.53902142 -0.05534150
[2,] -0.53878561 0.84219645 0.02037687
[3,] 0.05759199 0.01269102 0.99825954
So the eigenvalues of the covariance matrix are the squares of the standard deviations (i.e, variances) of the principal components and the principal components themselves are same as eigenvectors of covariance matrix (though signs may be opposite as they are here).
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$\begingroup$ Thanks for providing the details. A bit of searching produced this link, where
fa
from thepsych
package is used: stats.stackexchange.com/questions/31948/… $\endgroup$ Jul 15, 2014 at 22:19