how to compare two percentages to prove for statistical significance I have problem to compare the two percentages and to get the statistical significance for these two different percentage. I just want to approve whether these two percentages are significant or not significant using Microsoft Excel or SPSS. I attach with the image of my data. 

Hopefully your help may lead me to correct method. Thank you.
 A: Assuming you have the underlying numbers (as @gung asks), this is a classic case for a $\chi^2$ test. This is a basic test of association, and will give you a p-value to assess statistical significance. Just beware that $\chi^2$ tests are sensitive to sample size, so if you have a large sample, even small, non-substantive differences may come up as significant. I like to pair my $\chi^2$ tests with an effect size, which gets more at whether the difference is important. To calculate the effect size for a cross tab, use Cohen's w, which is easily created by calculating the standardized $\chi^2$ statistic - this is just calculating $\chi^2$ where the cell values are the overall table proportions (where the cell value is $N_{cell}/N_{table}$) (reference:  Cohen, J. (1992). Statistical Power Analysis. Current Directions in Psychological Science, 1(3), 98–101).
SPSS does it easily in its crosstab function. I think you have to hand calculate the $\chi^2$ statistic in Excel and then use one of its distribution formulas to get the p-value.
This link gives you more details on it, or you could refer to any introductory statistics text. This link and this link give you how to do it in SPSS.
