I'm assuming that when you say
11x11x10 you mean that you have a layer with 10, 11x11 filters. So the number of convolutions that you'll be doing is simply 10, 2D discrete convolution per filter in your filter bank. So, let's say that you have a network:
480x480x1 # your input image of 1 channel
11x11x10 # your first filter bank of 10, 11x11 filters
5x5x20 # your second filter bank of 20, 5x5 filters
4x4x100 # your final filter bank of 100, 4x4 filters
You're going to be doing: $10 + 20 + 100 = 130$ multi channel 2D convolutions each with a depth of 1, 10, and 20 respectively. As you can see, the depth of each convolution is going to change as a function of the depth of the input volume from the previous layer.
But I assumed that you're trying to figure out how to compare this to a single channel 2D convolution. Well, you could just multiply the depth of each input volume by the number of filters in each layer and add them together. In your case: $10 + 200 + 2000 = 2,210$.
Now this only tells you how many single channel 2D convolutions you're doing, not how computationally intensive each convolution is, the computational intensity of each convolution will depend on a variety of parameters including
stride (how far you step between each individual filter calculation), the number of pooling layers you have, etc.