The standard deviation in my original sample is very large, about 100 or so. I took many bootstrap samples, found the mean of each bootstrap sample and then took the mean of these means. I found the standard deviation of the means of my bootstrap samples from this 'mean of means' to be approximately 10.
My question is: when finding a confidence interval for the population mean, do I need to divide this value of '10' by sqrt(n-1) where n is my sample size?
mean(original_sample)+-1.96*10/sqrt(n-1)
It's just that my standard deviation has dropped so much, from 100 to 10, that maybe the factor of sqrt(n-1) has somehow been accounted for already?