Take an example of a linear regression,

$Y= \beta X$

where X and Y values are z-score transformed ($\mu$ = 0, $\sigma$ = 1).

In this situation the correlation coefficient $r$ equals $\beta$ because the following equality

$\beta = r \sigma_y/\sigma_x $.

While deriving bootstrap confidence intervals, I was surprised by the observation that beta and r have different bootstrap distributions:

enter image description here

The mean of these two distributions coincides with each other. However the confidence intervals are different, while confidence interval of $r$ includes zero, this was not true for the confidence interval of $\beta$, suggesting a significant contribution. Based on the observation on $\beta$, one might conclude that the regression is significant, whereas $r$ is not different than zero.

It was interesting (well at least for me) to realize that the equality of $\beta$ and $r$ in the equation above, does not imply equality of their distributions. I would be happy to learn more what is really happening here.


1 Answer 1


This is because the linear regression estimator $\bar \beta$ makes use of the information that $X$ and $Y$ are centered whereas the estimator $\bar \rho$ for the correlation coefficient has to subtract the empirical mean of $X$ and $Y$. In this case, the variance of $\bar \beta$ is lower than the variance of $\bar \rho$ (in a similar fashion as to estimate the variance when the mean is know).

  • $\begingroup$ so but then the distribution of $\beta$ should have higher variance, not the $r$. $\endgroup$
    – bonobo
    Commented Jul 24, 2015 at 11:28

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