If I have a artificial neuron with 2 inputs:
input 1 = 0.7 & weight = 0.7
input 2 = 0.3 & weight = 0.3
If I use a Rectifier Linear (ReLU) as activation function ($f(x)=max(0,x)$) is the output of this neuron:
Outcome 1: {I assume this is correct}: ReLU = $max(0,0.7*0.7+0.3*0.3) = 0.58$
or
Outcome 2: ReLU = $max(0,0.7*0.7,0.3*0.3) = 0.49 $
Or in other words: is this max taken over the summation or individual inputs? As I see ReLU as a drop in replacement for sigmoid/tanh I expect the first one is correct.
Question 1: is outcome 1 or 2 the correct way of calculating ReLU
I started to hesistate because of maxout which is defined in the paper as:
$ h_i = \max_{j \in [1, k]} z_{ij} $ with $z_{ij} = x^T W_{ij} + b_{ij}$, $ W \in \mathbb{R}^{d \times m \times k} $ and $b \in \mathbb{R}^{m \times k}$
Based on this definition I expect that the output of this neuron if maxout is used as activation is: $max(0.7*0.7,0.3*0.3) = 0.49$
Question 2: is this the correct way of calculating maxout for 1 layer with 1 neuron with these 2 input/weights??
The reason why I hesistate about the maxout/ReLU algo impls is because of the following phrase in this paper:
The only difference between maxout and max pooling over a set of rectified linear units is that maxout does not include a 0 in the max.
This suggests (to me) that $ReLU == MaxOut$ if the maximum $value > 0$ so that outcome 2 is correct where I first (still) assume outcome 1 is correct.