I thought that the canonical link function $g(\cdot)$ comes from the natural parameter of exponential family. Say, consider the family $$ f(y,\theta,\psi)=\exp\left\{\frac{y\theta-b(\theta)}{a(\psi)}-c(y,\psi)\right\} $$ then $\theta=\theta(\mu)$ is the canonical link function. Take Bernoulli distribution as an example, we have $$ P(Y=y)=\mu^{y}(1-\mu)^{1-y}=\exp\left\{y\log\frac{\mu}{1-\mu}+\log{(1-\mu)}\right\} $$ So, the canonical link function $$g(\mu)=\log\frac{\mu}{1-\mu}$$
But when I see this slide, it claims that $$ g'(\mu)=\frac{1}{V(\mu)} $$ Though it can be easily verified for this particular distribution (and some other distributions, like Poisson distribution), I can't see the equivalence for the general case. Can anyone give hints? Thank you~