I'm working on Extreme Values Theory, and I found the following sufficient condition to find the domain of attraction of a distribution and the corresponding normalizing constants:

For sufficiently smooth distribution $F$ with density $f$, define $\displaystyle h(x) = \frac{1-F(x)}{f(x)}$; let $\displaystyle b_n = F^{-1} \left( 1 - \frac{1}{n} \right)$, $a_n = h(b_n)$ and $\displaystyle \xi = \lim_{x \rightarrow +\infty}{h'(x)}$. Then the distribution of the maxima $F^n(a_nx+b_n)$ converges to a GEV distribution with shape parameter $\xi$.

My questions:

  1. What are the exact conditions for this result? I guess "sufficiently smooth" means that there must exist a density; there is also a definition problem for $h(x)$ if $f(x)=0$: what are exactly the assumptions here?

  2. I've got a theoretical book on Extreme Values (Resnick 87) but I haven't found this result; so how do you prove it?



1 Answer 1


The result you stated is also known as the von Mises condition in Extreme Value Theory. You can find the proof as well as the exact technical conditions in theorem 1.1.8. of the book "Extreme value theory: An introduction" by Laurens de Haan and Ana Ferreira.

Here's the exact statement:

von Mises condition

Note that the right endpoint $x^*$ of a distribution function $F$ is defined as $x^*=\sup\{x: F(x)<1\}$.


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