Throwing two four-sided dice; min/max problems

Suppose two four-sided fair dice. Let $X = min(X_{1}, X_{2})$ and $Y = max(X_{1}, X_{2})$ where $X_{1}$ is the result of the first dice and $X_{2}$ the result of the second dice. What is the PMF of the joint probability distribution?

How do I solve this problem? So there are $4\cdot 4 = 16$ different outcomes. What I need to do is to find the probability of each $min, max$ combination. How do I do it?

• Well, you know that if $\min(X_1, X_2) = \max(X_1, X_2)$ then $X_1 = X_2 = \min(X_1, X_2)$, and if $\min(X_1, X_2) < \max(X_1, X_2)$ then you know the values of both dice, only not their order. This should help you solve the problem. Just enumerate all combinations for the min and max and add up probabilities. – dsaxton Dec 8 '15 at 20:31
• As an aside, I think I've seen this exact problem somewhere before. Is it published in a textbook perhaps? I'd be interested in the reference. – Sycorax Dec 8 '15 at 20:36
• Probably, it sounds like a lot of other probability exercises. – dsaxton Dec 8 '15 at 21:42
• Welcome to Cross Validated! Please add the self-study tag, read its tag-wiki and modify your question to follow the guidelines on asking such questions. In particular, you'll need to clearly identify what you've done to solve the problem yourself, and indicate the specific help you need at the point you struck difficulty. – Glen_b Dec 9 '15 at 1:03

Now, we would like to obtain the joint probability mass function of $(X,Y)$. we can do this by simply counting the number of ways each combination of $x$ and $Y$ can occur and then dividing by the total number of ways which is 16.