I am trying to find a possible candidate as a fitting function for a distribution that looks like the following

enter image description here

I know that this isn't a straightforward question, but I would like a simple function to start working with, before starting to optimize the procedure.

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    $\begingroup$ do you have grounds to believe that the apparent skewness is not just small-sample variability? Is "entries" = sample size? $\endgroup$ – Christoph Hanck Dec 23 '15 at 12:20
  • $\begingroup$ @ChristophHanck : Thank you very much for your comment. Actually I expect this skewness. This histogram is the projection of a 2D histogram so I can see what I expect. And entries is actually the integral of the distribution. $\endgroup$ – Thanos Dec 23 '15 at 12:23

There is a family of distributions called the skew normal which includes an additional parameter for skewness. The normal distribution is a special case of the skew normal. Note that this distribution has limited flexibility on how much skewness there can be, with the skewness bounded between $-1$ and $1$ across the range of parameter values. For more info, read here.


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