# Can we make Random Forest 100% interpretable by fixing the seed?

Say I want to "visualize" in some way Random Forest (or make it implementable). All of my points come from the idea of fixing the seeds.

Let $z_1$ be the seed in the creation of boostrapped training set, and $z_2$ be the seed in the selection of feature's subset (for simplification, I only list 2 kinds of seeds here).

1. From $z_1$, $m$ boostrapped training sets are created: $D_1(z_1)$, $D_2(z_1)$, $D_3(z_1)$, ..., $D_m(z_1)$.
2. From those traning sets, $m$ corresponding decision trees are created, and tuned via cross-validation: $T_1(z_1,z_2)$, $T_2(z_1,z_2)$, $T_3(z_1,z_2)$,..., $T_m(z_1,z_2)$.
3. Let's denote predictions from the ${j^\text{th}}_{(j=1,2,...,m)}$ tree for an individual $x_i$ (from training or testing set, whatever) as $\hat{f}^j(x_i)_{(i \le n, j \le m)}$. Hence the final predictions by the ensemble trees are: $$\hat{F}(x_i) = \frac{1}{m}\sum\limits_{j=1}^m \hat{f}^j(x_i)$$
4. Once the model is validated, and is stable (meaning $\hat{F}(x_i)$ doesn't depend strongly on the pair $(z_1,z_2)$). I start to create every possible combinations of my features, which give me a very big set ($x'_i$).
5. Applying my forest on each $x'_i$ gives me the corresponding predictions: $$x'_1 \rightarrow \hat{F}(x'_1) \text{ - which is fixed thanks to (z_1, z_2)}$$ $$x'_2 \rightarrow \hat{F}(x'_2) \text{ - which is fixed thanks to (z_1, z_2)}$$ $$x'_3 \rightarrow \hat{F}(x'_3) \text{ - which is fixed thanks to (z_1, z_2)}$$ $$x'_4 \rightarrow \hat{F}(x'_4) \text{ - which is fixed thanks to (z_1, z_2)}$$ $$....$$
6. The latter can be easily represented in form of a single (huge) tree. For example: $x'_1$: (Age = 18, sex = M, ...), $x'_2$ = (Age = 18, sex = F, ...), ... could be regrouped to create a leaf.

This works also for every ensemble methods based on aggregation of trees.

It will be computationally expensive, but is there any thing wrong with this approach?

• I don't understand what's happening in steps 4,5,6. Can you explain this in more detail? For example, what does it mean for predictions to be "the same for each case"? Do you mean that decisions must be fixed because fixing the seed makes the model deterministic? – Sycorax Jan 21 '16 at 16:10
• @user777: yes, I edited the question! – Metariat Jan 21 '16 at 18:43
• "not so random" forest? – Aksakal Jan 21 '16 at 18:48
• Your problem is in step 5. Age = 18, sex = M can be price = 18 for one tree, price = 19 for another tree, and price =20 for another tree. The ensemble will collect these different values in some way, like an average, but all you're doing by fixing the seed is making the forest reproducible. – Sycorax Jan 21 '16 at 18:48
• On general note, if your decision is dependent on the seed you have an issue. Ultimately the model is built to make a decision. Fixing the seed hides the problem. – Aksakal Jan 21 '16 at 18:54