# Die Probability Question

I have this question which I can't figure out, maybe because the answer I got is not correct (trying to match the answer).

A six-sided die is thrown twice, but not a normal die. If X is the result of the die, then:

$$P(X=1)=P(X=4)=0.2$$

$$P(X=2)=P(X=3)=P(X=6)=0.1$$

$$P(X=5)=0.3$$

I am interested in the probability of getting an even number twice.

The answer I got is 0.06.

I can't figure out why... the explanation is:

$$0.04+2*0.01$$

But it makes no sense to me.

• You calculated the probability of getting an even number and then that same even number again. – AlexR Jun 6 '16 at 22:06

$$P(Even) = P(2)+P(4)+P(6)$$ $$~~~~~~= 0.1+0.2+0.1$$ $$= 0.4~~~~~~~~~~~~~$$