This question came up at work when someone asked me what the relationship was between a percentile and a confidence interval, and I had a very hard time articulating my thoughts. The context was a very simple question regarding estimating a 95% confidence interval on a sample mean.
I understand that the central limit theorem states that the sampling distribution of the mean of any independent, random variable will be normal or nearly normal, if the sample size is large enough. Thus, the sample mean has a normal distribution $N(\bar{x}, s/\sqrt{n})$ where $s$ is the sample standard deviation.
Now, let's say that the null hypothesis $H_0: \mu_{\bar{x}} = \mu$ is true. Then under the null hypothesis, the 95% confidence interval around the sample mean is $\mu_{\bar{x}} \pm 1.96 * s/\sqrt{n}$
The question from my coworker was specifically the following: the standard error is just the standard deviation of the sampling distribution of the mean. Thus, would $\mu_{\bar{x}} + 1.96 * s/\sqrt{n}$ be equivalent to the 97.5 percentile of a distribution created by calculating the sample means of many samples of size $n$?
The question was really odd to me because percentiles and confidence intervals are two separate concepts and my coworker's question was asking about the relationship between the two, and I got very confused but couldn't articulate my points.